Answer key · Set C
Choosing With Care
1The mean is 8, The median is 8 The dots add to 72 and 72 ÷ 9 = 8. The 5th dot is 8. No dot is far from the rest.
25.5 The 4th dot is 5 and the 5th dot is 6. Halfway between them is 5.5.
37.25 58 ÷ 8 = 7.25.
4The median, 5.5 The mean, 7.25, is above all seven of the bunched dots because of the far dot. The median, 5.5, sits in the crowd.
5True Without the dot at 23 the mean drops from 7.25 to 5. The median only moves from 5.5 to 5.
6The median The mean goes from 6 to 7.4 and the range from 4 to 16. The median stays at 6.
77.4 74 ÷ 10 = 7.4.
8Plot B, Plot C B and C each have one dot far from the rest. A is balanced, so the mean is fine.
9Class B Class A runs from 5 to 7, a range of 2. Class B runs from 2 to 9, a range of 7.
101-B, 2-A, 3-C A far value pulls the mean, so use the median. Balanced data lets you use the mean. The IQR is the spread of the middle half.
11The median, 7 minutes Four of the five friends read 8 minutes or less. The median, 7, matches them. The mean, 10, is higher than four of the five.
12Your own words: a grown-up reads it.
Mark each answer, count the right ones and write the score on the sheet.